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Section
III
Questions 6 - 12:
Question 6
D Following
the example given and look at the carbon which becomes bonded to the benzene
ring. This must be the carbon which formed part of the double bond and carried
two methyl groups. As such the new C bonded to the ring is also bonded to two
methyl groups.
Question 7
A Carry out the rearrangement and
work out the position of the new double bonds, one must be adjacent to the
aldehyde group.
Question 8
B The product is :
Question 9
C see above product
Question 10
B Join the two carbon atoms mentioned. Two
double bonds must remain in what was the benzene ring. This leads to answer B
Question 11
B One of the alcohol groups forms the carbonyl
on carbon 10. The new carbon atom on here, which makes the six membered ring,
must have come from a carbon atom one away, in the original compound. Hence the
two OH groups must have been next to each other in the original compound.
Question 12
B Very simply this is where the new bond in the
six membered ring is formed.
NEXT
SECTION
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